LinkedList底层解析
概述
LinkedList同时实现了List接口和Deque接口,也就是说它既可以看作一个顺序集合,又可以看作一个队列(Queue),同时还可以看作一个栈(Stack)。与ArrayList不同,LinkedList基于链表实现,添加和删除元素效率高。
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public class LinkedList<E>
extends AbstractSequentialList<E>
implements List<E>, Deque<E>, Cloneable, java.io.Serializable
{}
底层数据结构
LinkedList的底层通过==双向连表实现==,每个节点用内部类Node表示。LinkedList通 first 和 last 引用分别指向连表的第一个和最后一个元素,当链表为空的时候,first 和 last 都指向==null==。
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transient int size = 0;
/**
* Pointer to first node.
* Invariant: (first == null && last == null) ||
* (first.prev == null && first.item != null)
*/
transient Node<E> first;
/**
* Pointer to last node.
* Invariant: (first == null && last == null) ||
* (last.next == null && last.item != null)
*/
transient Node<E> last;
其中Node是私有的内部类
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private static class Node<E> {
E item;
Node<E> next;
Node<E> prev;
Node(Node<E> prev, E element, Node<E> next) {
this.item = element;
this.next = next;
this.prev = prev;
}
}
构造函数:
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/**
* Constructs an empty list.
*/
public LinkedList() {
}
/**
* Constructs a list containing the elements of the specified
* collection, in the order they are returned by the collection's
* iterator.
*
* @param c the collection whose elements are to be placed into this list
* @throws NullPointerException if the specified collection is null
*/
public LinkedList(Collection<? extends E> c) {
this();
addAll(c);
}
一个无参构造和一个传入集合的构造器。
add()
add()方法有两种:
- add(E e):在LinkedList的末尾插入元素(last指向链表末尾)
- add(int index , E element):在指定下标处插入元素
add(E e)就类似于双向链表的尾插法
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/**
* Appends the specified element to the end of this list.
*
* <p>This method is equivalent to {@link #addLast}.
*
* @param e element to be appended to this list
* @return {@code true} (as specified by {@link Collection#add})
*/
public boolean add(E e) {
linkLast(e);
return true;
}
/**
* Links e as last element.
*/
void linkLast(E e) {
final Node<E> l = last;
final Node<E> newNode = new Node<>(l, e, null);
last = newNode;
if (l == null)
first = newNode;
else
l.next = newNode;
size++;
modCount++;
}
同理,add(int index, E element)就类似于双向链表的插入,当index==size时,就相当于add(E e);若不是,则:
- 根据index找到要插入的位置,即node(int index)方法
- 完成插入操作
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/**
* Inserts the specified element at the specified position in this list.
* Shifts the element currently at that position (if any) and any
* subsequent elements to the right (adds one to their indices).
*
* @param index index at which the specified element is to be inserted
* @param element element to be inserted
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public void add(int index, E element) {
checkPositionIndex(index);
if (index == size)
linkLast(element);
else
linkBefore(element, node(index));
}
Node<E> node(int index) {
// assert isElementIndex(index);
if (index < (size >> 1)) {
Node<E> x = first;
for (int i = 0; i < index; i++)
x = x.next;
return x;
} else {
Node<E> x = last;
for (int i = size - 1; i > index; i--)
x = x.prev;
return x;
}
}
// Inserts element e before non-null Node succ.
void linkBefore(E e, Node<E> succ) {
// assert succ != null;
final Node<E> pred = succ.prev;
final Node<E> newNode = new Node<>(pred, e, succ);
succ.prev = newNode;
if (pred == null)
first = newNode;
else
pred.next = newNode;
size++;
modCount++;
}
可以看到对于node方法,需要根据index < size >> 1来确定是从前往后遍历,还是从后往前遍历(靠近哪个端)。这里相较于arrayList的元素检索(数组下标检索),效率就低了。
addAll()
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/**
* Appends all of the elements in the specified collection to the end of
* this list, in the order that they are returned by the specified
* collection's iterator. The behavior of this operation is undefined if
* the specified collection is modified while the operation is in
* progress. (Note that this will occur if the specified collection is
* this list, and it's nonempty.)
*
* @param c collection containing elements to be added to this list
* @return {@code true} if this list changed as a result of the call
* @throws NullPointerException if the specified collection is null
*/
public boolean addAll(Collection<? extends E> c) {
return addAll(size, c);
}
/**
* Inserts all of the elements in the specified collection into this
* list, starting at the specified position. Shifts the element
* currently at that position (if any) and any subsequent elements to
* the right (increases their indices). The new elements will appear
* in the list in the order that they are returned by the
* specified collection's iterator.
*
* @param index index at which to insert the first element
* from the specified collection
* @param c collection containing elements to be added to this list
* @return {@code true} if this list changed as a result of the call
* @throws IndexOutOfBoundsException {@inheritDoc}
* @throws NullPointerException if the specified collection is null
*/
public boolean addAll(int index, Collection<? extends E> c) {
checkPositionIndex(index);
Object[] a = c.toArray();
int numNew = a.length;
if (numNew == 0)
return false;
Node<E> pred, succ;
if (index == size) {
succ = null;
pred = last;
} else {
succ = node(index);
pred = succ.prev;
}
for (Object o : a) {
@SuppressWarnings("unchecked") E e = (E) o;
Node<E> newNode = new Node<>(pred, e, null);
if (pred == null)
first = newNode;
else
pred.next = newNode;
pred = newNode;
}
if (succ == null) {
last = pred;
} else {
pred.next = succ;
succ.prev = pred;
}
size += numNew;
modCount++;
return true;
}
addAll()方法并未直接调用add(int indec, E element),主要考虑到效率问题。
get元素
LinkedList共有3个获取元素的方法
- getFirst()
- getLast()
- get(int index)
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/**
* Returns the first element in this list.
*
* @return the first element in this list
* @throws NoSuchElementException if this list is empty
*/
public E getFirst() {
final Node<E> f = first;
if (f == null)
throw new NoSuchElementException();
return f.item;
}
/**
* Returns the last element in this list.
*
* @return the last element in this list
* @throws NoSuchElementException if this list is empty
*/
public E getLast() {
final Node<E> l = last;
if (l == null)
throw new NoSuchElementException();
return l.item;
}
public E get(int index) {
checkElementIndex(index);
return node(index).item;
}
remove元素
LinkedList共有5个删除元素的方法
- removeFirst()
- removeLast()
- remove(E e)
- remove(int index)
- void clear()
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public E removeFirst() {
final Node<E> f = first;
if (f == null)
throw new NoSuchElementException();
return unlinkFirst(f);
}
public E removeLast() {
final Node<E> l = last;
if (l == null)
throw new NoSuchElementException();
return unlinkLast(l);
}
public boolean remove(Object o) {
if (o == null) {
for (Node<E> x = first; x != null; x = x.next) {
if (x.item == null) {
unlink(x);
return true;
}
}
} else {
for (Node<E> x = first; x != null; x = x.next) {
if (o.equals(x.item)) {
unlink(x);
return true;
}
}
}
return false;
}
public E remove(int index) {
checkElementIndex(index);
return unlink(node(index));
}
其核心都是调用 *unlink(Node
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E unlink(Node<E> x) {
// assert x != null;
// 待删除节点
final E element = x.item;
// 此节点的前后节点
final Node<E> next = x.next;
final Node<E> prev = x.prev;
if (prev == null) {
first = next;
} else {
prev.next = next;
x.prev = null;
}
if (next == null) {
last = prev;
} else {
next.prev = prev;
x.next = null;
}
// 将当前节点元素置为null,方便GC回收
x.item = null;
size--;
modCount++;
return element;
}
核心流程如下:
- 首先获取待删除节点及其前后节点;
- 判断待删除节点是否为头/尾节点:
- 若 x 为头节点,则将first指向 x.next 节点
- 若 x 为尾节点,则将last指向 x.prev 节点
- 其他情况则执行下一步操作
- 将 x 前一个节点的 next 指向 x 的后一个节点,将 x 的后一个节点的 prev 指向 x 的前一个节点
- 将待 x 元素置空,方便GC回收,修改链表长度
对于 clear()方法,其主要是遍历链表,并将node之间的引用关系置空,方便GC回收
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/**
* Removes all of the elements from this list.
* The list will be empty after this call returns.
*/
public void clear() {
// Clearing all of the links between nodes is "unnecessary", but:
// - helps a generational GC if the discarded nodes inhabit
// more than one generation
// - is sure to free memory even if there is a reachable Iterator
for (Node<E> x = first; x != null; ) {
Node<E> next = x.next;
x.item = null;
x.next = null;
x.prev = null;
x = next;
}
first = last = null;
size = 0;
modCount++;
}
查找元素
查找的本质就是去寻找元素的下标位置,主要是采用 Object.equals来比对对象。
- indexOf(Object o):查找第一次出现的index
- LastIndexOf(Object o):查找最后一次出现的index
这里就是我对于LinkedList的主要分析,当然其中还实现了 Queue 、Deque 的方法,有兴趣可以去看一看,这里不做过多介绍。
参考文章:
- https://pdai.tech/md/java/collection/java-collection-LinkedList.html
- https://javaguide.cn/java/collection/linkedlist-source-code.html
